{ "format" : "linked-data-api", "version" : "0.2", "result" : {"_about" : "https://vocabs.ardc.edu.au/repository/api/lda/aas/the-unified-astronomy-thesaurus/5-0-0/resource.text?uri=http://astrothesaurus.org/uat/1404", "definition" : "https://vocabs.ardc.edu.au/repository/api/lda/aas/the-unified-astronomy-thesaurus/5-0-0/resource.text?uri=http://astrothesaurus.org/uat/1404", "extendedMetadataVersion" : "https://vocabs.ardc.edu.au/repository/api/lda/aas/the-unified-astronomy-thesaurus/5-0-0/resource.text?_metadata=all&uri=http://astrothesaurus.org/uat/1404", "primaryTopic" : {"_about" : "http://astrothesaurus.org/uat/1404", "altLabel" : [{"_value" : "Roche radius", "_lang" : "en"}
      ], "broader" : [{"_about" : "http://astrothesaurus.org/uat/1695", "narrower" : ["http://astrothesaurus.org/uat/1404"]}
      , {"_about" : "http://astrothesaurus.org/uat/1699", "narrower" : ["http://astrothesaurus.org/uat/1404"]}
      ], "contributor" : "http://editor.vocabs.ands.org.au/user/AAS_Frey.Katie_Admin", "dctermsModified" : "Tue, 24 Nov 2020 16:49:39 GMT+0000", "definition" : "The smallest distance at which a satellite under the influence of its own gravitation and that of a central mass about which it is describing a Keplerian orbit can be in equilibrium. This does not, however, apply to a body held together by the stronger forces between atoms and molecules. At a lesser distance the tidal forces of the primary body would break up the secondary body. The Roche limit is given by the formula d = 1.26 R_M (ρ_M/ρ_m)^(1/3), where R_M is the radius of the primary body, ρ_M is the density of the primary, and ρ_m is the density of the secondary body. This formula can also be expressed as: d = 1.26 R_m (M_M/M_m)^(1/3), where R_m is the radius of the secondary. As an example, for the Earth-Moon system, where R_M = 6,378 km, ρ_M = 5.5 g cm^(-3), and ρ_m = 2.5 g cm^(-3) is 1.68 Earth radii.", "prefLabel" : {"_value" : "Roche limit", "_lang" : "en"}
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